Q:

How do you write y+1=4/5(x-3) in standard form?

Accepted Solution

A:
Answer:The standard form of the given expression is [tex] - (\frac{4}{5})x + y +  (\frac{17}{5})   = 0[/tex]Step-by-step explanation:Here, the given expression is  [tex]y + 1 = \frac{4}{5}  (x-3)[/tex]Now, the Standard Form of the equation is ax + by + c = 0Solving this, we get: [tex]y + 1 = \frac{4}{5}  (x-3)  \implies y + 1 = (\frac{4}{5})x  - \frac{12}{5}[/tex]⇒[tex]y + 1   - (\frac{4}{5})x + (\frac{12}{5})  = 0[/tex]or, [tex]y  - (\frac{4}{5})x + (\frac{12}{5}  + 1 )= 0  \implies y  - (\frac{4}{5})x + (\frac{12+ 5}{5})   = 0[/tex]⇒[tex]y  - (\frac{4}{5})x + (\frac{17}{5})   = 0[/tex]Hence, the standard form of the given expression is [tex]  - (\frac{4}{5})x + y + (\frac{17}{5})   = 0[/tex]